1311123130301 has 4 divisors (see below), whose sum is σ = 1311135002112. Its totient is φ = 1311111258492.

The previous prime is 1311123130243. The next prime is 1311123130307. The reversal of 1311123130301 is 1030313211131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311123130301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311123130307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5768675 + ... + 5991648.

It is an arithmetic number, because the mean of its divisors is an integer number (327783750528).

Almost surely, 2^{1311123130301} is an apocalyptic number.

It is an amenable number.

1311123130301 is a deficient number, since it is larger than the sum of its proper divisors (11871811).

1311123130301 is a wasteful number, since it uses less digits than its factorization.

1311123130301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11871810.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1311123130301 its reverse (1030313211131), we get a palindrome (2341436341432).

The spelling of 1311123130301 in words is "one trillion, three hundred eleven billion, one hundred twenty-three million, one hundred thirty thousand, three hundred one".