Base | Representation |
---|---|
bin | 111101000011011110… |
… | …0011001110010101111 |
3 | 110112102111020111202011 |
4 | 1322012330121302233 |
5 | 4122004412000421 |
6 | 140122114342051 |
7 | 12321050053432 |
oct | 1720674316257 |
9 | 415374214664 |
10 | 131113000111 |
11 | 50671963635 |
12 | 214b158a927 |
13 | c496657792 |
14 | 64bb22d819 |
15 | 36259164e1 |
hex | 1e86f19caf |
131113000111 has 4 divisors (see below), whose sum is σ = 131201056000. Its totient is φ = 131024944224.
The previous prime is 131113000099. The next prime is 131113000121. The reversal of 131113000111 is 111000311131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131113000111 - 211 = 131112998063 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131113000091 and 131113000100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131113000121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44025711 + ... + 44028688.
It is an arithmetic number, because the mean of its divisors is an integer number (32800264000).
Almost surely, 2131113000111 is an apocalyptic number.
131113000111 is a deficient number, since it is larger than the sum of its proper divisors (88055889).
131113000111 is an equidigital number, since it uses as much as digits as its factorization.
131113000111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88055888.
The product of its (nonzero) digits is 9, while the sum is 13.
Adding to 131113000111 its reverse (111000311131), we get a palindrome (242113311242).
The spelling of 131113000111 in words is "one hundred thirty-one billion, one hundred thirteen million, one hundred eleven", and thus it is an aban number.
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