Base | Representation |
---|---|
bin | 111101000011011110… |
… | …0011001110100100111 |
3 | 110112102111020111220121 |
4 | 1322012330121310213 |
5 | 4122004412001411 |
6 | 140122114342411 |
7 | 12321050053663 |
oct | 1720674316447 |
9 | 415374214817 |
10 | 131113000231 |
11 | 50671963734 |
12 | 214b158aa07 |
13 | c496657855 |
14 | 64bb22d8a3 |
15 | 3625916571 |
hex | 1e86f19d27 |
131113000231 has 4 divisors (see below), whose sum is σ = 135634138200. Its totient is φ = 126591862264.
The previous prime is 131113000223. The next prime is 131113000253. The reversal of 131113000231 is 132000311131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131113000231 - 23 = 131113000223 is a prime.
It is a super-2 number, since 2×1311130002312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131113000211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2260568941 + ... + 2260568998.
It is an arithmetic number, because the mean of its divisors is an integer number (33908534550).
Almost surely, 2131113000231 is an apocalyptic number.
131113000231 is a deficient number, since it is larger than the sum of its proper divisors (4521137969).
131113000231 is an equidigital number, since it uses as much as digits as its factorization.
131113000231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4521137968.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131113000231 its reverse (132000311131), we get a palindrome (263113311362).
The spelling of 131113000231 in words is "one hundred thirty-one billion, one hundred thirteen million, two hundred thirty-one", and thus it is an aban number.
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