13111311301 has 4 divisors (see below), whose sum is σ = 14303248704. Its totient is φ = 11919373900.

The previous prime is 13111311293. The next prime is 13111311341. The reversal of 13111311301 is 10311311131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13111311301 - 2³ = 13111311293 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111311341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 595968685 + ... + 595968706.

It is an arithmetic number, because the mean of its divisors is an integer number (3575812176).

Almost surely, 2^13111311301 is an apocalyptic number.

13111311301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13111311301 is a deficient number, since it is larger than the sum of its proper divisors (1191937403).

13111311301 is a wasteful number, since it uses less digits than its factorization.

13111311301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1191937402.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 13111311301 its reverse (10311311131), we get a palindrome (23422622432).

The spelling of 13111311301 in words is "thirteen billion, one hundred eleven million, three hundred eleven thousand, three hundred one".