13111315366343 has 8 divisors (see below), whose sum is σ = 14486159177568. Its totient is φ = 11803537106944.

The previous prime is 13111315366337. The next prime is 13111315366361. The reversal of 13111315366343 is 34366351311131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13111315366343 - 2¹⁴ = 13111315349959 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13111315366343.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111315366363) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16766387546 + ... + 16766388327.

It is an arithmetic number, because the mean of its divisors is an integer number (1810769897196).

Almost surely, 2^{13111315366343} is an apocalyptic number.

13111315366343 is a deficient number, since it is larger than the sum of its proper divisors (1374843811225).

13111315366343 is a wasteful number, since it uses less digits than its factorization.

13111315366343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33532775913.

The product of its digits is 174960, while the sum is 41.

Adding to 13111315366343 its reverse (34366351311131), we get a palindrome (47477666677474).

The spelling of 13111315366343 in words is "thirteen trillion, one hundred eleven billion, three hundred fifteen million, three hundred sixty-six thousand, three hundred forty-three".