Search a number
-
+
131113201101 = 3251174121117
BaseRepresentation
bin111101000011011110…
…1001010110111001101
3110112102111121201110020
41322012331022313031
54122004434413401
6140122122532353
712321051551421
oct1720675126715
9415374551406
10131113201101
1150671a90643
12214b16670b9
13c4966c80cc
1464bb282b81
153625955d36
hex1e86f4adcd

131113201101 has 8 divisors (see below), whose sum is σ = 175514086944. Its totient is φ = 87060558000.

The previous prime is 131113201091. The next prime is 131113201129. The reversal of 131113201101 is 101102311131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-131113201101 is a prime.

It is a super-3 number, since 3×1311132011013 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131113201601) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 87059806 + ... + 87061311.

It is an arithmetic number, because the mean of its divisors is an integer number (21939260868).

Almost surely, 2131113201101 is an apocalyptic number.

It is an amenable number.

131113201101 is a deficient number, since it is larger than the sum of its proper divisors (44400885843).

131113201101 is a wasteful number, since it uses less digits than its factorization.

131113201101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 174121371.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 131113201101 its reverse (101102311131), we get a palindrome (232215512232).

The spelling of 131113201101 in words is "one hundred thirty-one billion, one hundred thirteen million, two hundred one thousand, one hundred one".

Divisors: 1 3 251 753 174121117 522363351 43704400367 131113201101