Base | Representation |
---|---|
bin | 1011111011001011011110… |
… | …0101000000101100100111 |
3 | 1201102102121102221112222201 |
4 | 2332302313211000230213 |
5 | 3204303440422320403 |
6 | 43515131325035331 |
7 | 2522155510121452 |
oct | 276626745005447 |
9 | 51372542845881 |
10 | 13111320120103 |
11 | 41a553043a657 |
12 | 157908a6b5b47 |
13 | 74151381627a |
14 | 33483c686499 |
15 | 17b0c75e621d |
hex | becb7940b27 |
13111320120103 has 8 divisors (see below), whose sum is σ = 13144164834096. Its totient is φ = 13078476144000.
The previous prime is 13111320120079. The next prime is 13111320120113. The reversal of 13111320120103 is 30102102311131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13111320120103 - 29 = 13111320119591 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13111320120113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59551300 + ... + 59771062.
It is an arithmetic number, because the mean of its divisors is an integer number (1643020604262).
Almost surely, 213111320120103 is an apocalyptic number.
13111320120103 is a deficient number, since it is larger than the sum of its proper divisors (32844713993).
13111320120103 is a wasteful number, since it uses less digits than its factorization.
13111320120103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 368945.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 13111320120103 its reverse (30102102311131), we get a palindrome (43213422431234).
The spelling of 13111320120103 in words is "thirteen trillion, one hundred eleven billion, three hundred twenty million, one hundred twenty thousand, one hundred three".
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