Base | Representation |
---|---|
bin | 11101110011111100101011… |
… | …110010100100010100010001 |
3 | 122012020022002102200122210000 |
4 | 131303330223302210110101 |
5 | 114141124314014234413 |
6 | 1142504323445400213 |
7 | 36421421232623145 |
oct | 3563745362442421 |
9 | 565208072618700 |
10 | 131113201321233 |
11 | 3885a88403925a |
12 | 12856749a09069 |
13 | 5820bca35c931 |
14 | 2453caca39225 |
15 | 102584deb7073 |
hex | 773f2bca4511 |
131113201321233 has 40 divisors (see below), whose sum is σ = 201157282833320. Its totient is φ = 85045007496960.
The previous prime is 131113201321217. The next prime is 131113201321243. The reversal of 131113201321233 is 332123102311131.
131113201321233 is a `hidden beast` number, since 1 + 3 + 1 + 11 + 320 + 1 + 321 + 2 + 3 + 3 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 23858760318849 + 107254441002384 = 4884543^2 + 10356372^2 .
It is not a de Polignac number, because 131113201321233 - 24 = 131113201321217 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131113201321197 and 131113201321206.
It is not an unprimeable number, because it can be changed into a prime (131113201321243) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 201580203 + ... + 202229583.
It is an arithmetic number, because the mean of its divisors is an integer number (5028932070833).
Almost surely, 2131113201321233 is an apocalyptic number.
It is an amenable number.
131113201321233 is a deficient number, since it is larger than the sum of its proper divisors (70044081512087).
131113201321233 is an equidigital number, since it uses as much as digits as its factorization.
131113201321233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 716799 (or 716790 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 27.
Adding to 131113201321233 its reverse (332123102311131), we get a palindrome (463236303632364).
The spelling of 131113201321233 in words is "one hundred thirty-one trillion, one hundred thirteen billion, two hundred one million, three hundred twenty-one thousand, two hundred thirty-three".
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