Base | Representation |
---|---|
bin | 11101110011111100101011… |
… | …110010100100010011101101 |
3 | 122012020022002102200122201200 |
4 | 131303330223302210103231 |
5 | 114141124314014234242 |
6 | 1142504323445400113 |
7 | 36421421232623064 |
oct | 3563745362442355 |
9 | 565208072618650 |
10 | 131113201321197 |
11 | 3885a884039227 |
12 | 12856749a09039 |
13 | 5820bca35c904 |
14 | 2453caca391db |
15 | 102584deb704c |
hex | 773f2bca44ed |
131113201321197 has 24 divisors (see below), whose sum is σ = 189494803656288. Its totient is φ = 87358475709600.
The previous prime is 131113201321189. The next prime is 131113201321217. The reversal of 131113201321197 is 791123102311131.
131113201321197 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 1 + 320 + 1 + 321 + 1 + 9 + 7 = 666.
It is not a de Polignac number, because 131113201321197 - 23 = 131113201321189 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131113201321117) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 111710947 + ... + 112878527.
It is an arithmetic number, because the mean of its divisors is an integer number (7895616819012).
Almost surely, 2131113201321197 is an apocalyptic number.
It is an amenable number.
131113201321197 is a deficient number, since it is larger than the sum of its proper divisors (58381602335091).
131113201321197 is a wasteful number, since it uses less digits than its factorization.
131113201321197 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1174761 (or 1174758 counting only the distinct ones).
The product of its (nonzero) digits is 6804, while the sum is 36.
The spelling of 131113201321197 in words is "one hundred thirty-one trillion, one hundred thirteen billion, two hundred one million, three hundred twenty-one thousand, one hundred ninety-seven".
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