1311132013441 has 4 divisors (see below), whose sum is σ = 1333354590000. Its totient is φ = 1288909436884.

The previous prime is 1311132013423. The next prime is 1311132013447. The reversal of 1311132013441 is 1443102311131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311132013441 - 2⁵ = 1311132013409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311132013447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11111288191 + ... + 11111288308.

It is an arithmetic number, because the mean of its divisors is an integer number (333338647500).

Almost surely, 2^{1311132013441} is an apocalyptic number.

It is an amenable number.

1311132013441 is a deficient number, since it is larger than the sum of its proper divisors (22222576559).

1311132013441 is an equidigital number, since it uses as much as digits as its factorization.

1311132013441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22222576558.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1311132013441 its reverse (1443102311131), we get a palindrome (2754234324572).

The spelling of 1311132013441 in words is "one trillion, three hundred eleven billion, one hundred thirty-two million, thirteen thousand, four hundred forty-one".