13111320235045 has 16 divisors (see below), whose sum is σ = 16568463882240. Its totient is φ = 9932922869184.

The previous prime is 13111320234923. The next prime is 13111320235049. The reversal of 13111320235045 is 54053202311131.

It is a cyclic number.

It is not a de Polignac number, because 13111320235045 - 2³³ = 13102730300453 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13111320234998 and 13111320235016.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111320235049) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28084837 + ... + 28547866.

It is an arithmetic number, because the mean of its divisors is an integer number (1035528992640).

Almost surely, 2^{13111320235045} is an apocalyptic number.

It is an amenable number.

13111320235045 is a deficient number, since it is larger than the sum of its proper divisors (3457143647195).

13111320235045 is a wasteful number, since it uses less digits than its factorization.

13111320235045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56635164.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 13111320235045 its reverse (54053202311131), we get a palindrome (67164522546176).

The spelling of 13111320235045 in words is "thirteen trillion, one hundred eleven billion, three hundred twenty million, two hundred thirty-five thousand, forty-five".