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131113230301 = 479273722819
BaseRepresentation
bin111101000011011110…
…1010001111111011101
3110112102111200012111201
41322012331101333131
54122004441332201
6140122123315501
712321052032514
oct1720675217735
9415374605451
10131113230301
1150672000579
12214b167bb91
13c4967084a1
1464bb28d67b
15362595e801
hex1e86f51fdd

131113230301 has 4 divisors (see below), whose sum is σ = 131386953600. Its totient is φ = 130839507004.

The previous prime is 131113230293. The next prime is 131113230323. The reversal of 131113230301 is 103032311131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131113230301 - 23 = 131113230293 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131113230331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 136860931 + ... + 136861888.

It is an arithmetic number, because the mean of its divisors is an integer number (32846738400).

Almost surely, 2131113230301 is an apocalyptic number.

It is an amenable number.

131113230301 is a deficient number, since it is larger than the sum of its proper divisors (273723299).

131113230301 is an equidigital number, since it uses as much as digits as its factorization.

131113230301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 273723298.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 131113230301 its reverse (103032311131), we get a palindrome (234145541432).

The spelling of 131113230301 in words is "one hundred thirty-one billion, one hundred thirteen million, two hundred thirty thousand, three hundred one".

Divisors: 1 479 273722819 131113230301