13111324111 has 4 divisors (see below), whose sum is σ = 13198154224. Its totient is φ = 13024494000.

The previous prime is 13111324063. The next prime is 13111324123. The reversal of 13111324111 is 11142311131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13111324111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111324151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43414830 + ... + 43415131.

It is an arithmetic number, because the mean of its divisors is an integer number (3299538556).

Almost surely, 2^13111324111 is an apocalyptic number.

13111324111 is a deficient number, since it is larger than the sum of its proper divisors (86830113).

13111324111 is an equidigital number, since it uses as much as digits as its factorization.

13111324111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86830112.

The product of its digits is 72, while the sum is 19.

Adding to 13111324111 its reverse (11142311131), we get a palindrome (24253635242).

The spelling of 13111324111 in words is "thirteen billion, one hundred eleven million, three hundred twenty-four thousand, one hundred eleven".