Base | Representation |
---|---|
bin | 11000011011000000… |
… | …00001111110111111 |
3 | 1020211202102020212110 |
4 | 30031200001332333 |
5 | 203323004334211 |
6 | 10005010505103 |
7 | 642625040031 |
oct | 141540017677 |
9 | 36752366773 |
10 | 13111402431 |
11 | 5619054786 |
12 | 265ab95193 |
13 | 130c4a84ba |
14 | 8c5487c51 |
15 | 51b109ea6 |
hex | 30d801fbf |
13111402431 has 8 divisors (see below), whose sum is σ = 17484992640. Its totient is φ = 8739373592.
The previous prime is 13111402427. The next prime is 13111402441. The reversal of 13111402431 is 13420411131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13111402431 - 22 = 13111402427 is a prime.
It is a super-2 number, since 2×131114024312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13111402398 and 13111402407.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13111402411) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 370605 + ... + 404438.
It is an arithmetic number, because the mean of its divisors is an integer number (2185624080).
Almost surely, 213111402431 is an apocalyptic number.
13111402431 is a deficient number, since it is larger than the sum of its proper divisors (4373590209).
13111402431 is an equidigital number, since it uses as much as digits as its factorization.
13111402431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 780685.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 13111402431 its reverse (13420411131), we get a palindrome (26531813562).
The spelling of 13111402431 in words is "thirteen billion, one hundred eleven million, four hundred two thousand, four hundred thirty-one".
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