13111421213131 has 4 divisors (see below), whose sum is σ = 13115530091664. Its totient is φ = 13107312334600.

The previous prime is 13111421213113. The next prime is 13111421213161. The reversal of 13111421213131 is 13131212411131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13111421213131 - 2⁷ = 13111421213003 is a prime.

It is a super-3 number, since 3×13111421213131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13111421213096 and 13111421213105.

It is not an unprimeable number, because it can be changed into a prime (13111421213161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2054434480 + ... + 2054440861.

It is an arithmetic number, because the mean of its divisors is an integer number (3278882522916).

Almost surely, 2^{13111421213131} is an apocalyptic number.

13111421213131 is a deficient number, since it is larger than the sum of its proper divisors (4108878533).

13111421213131 is an equidigital number, since it uses as much as digits as its factorization.

13111421213131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4108878532.

The product of its digits is 432, while the sum is 25.

Adding to 13111421213131 its reverse (13131212411131), we get a palindrome (26242633624262).

The spelling of 13111421213131 in words is "thirteen trillion, one hundred eleven billion, four hundred twenty-one million, two hundred thirteen thousand, one hundred thirty-one".