Base | Representation |
---|---|
bin | 10011000101000110001… |
… | …010010011100101000010 |
3 | 11122100021202020101221222 |
4 | 103011012022103211002 |
5 | 132440204341211114 |
6 | 2442155210115042 |
7 | 163504216144340 |
oct | 23050612234502 |
9 | 4570252211858 |
10 | 1311142132034 |
11 | 466063608979 |
12 | 192136a1ba82 |
13 | 968425c7687 |
14 | 47661296990 |
15 | 2418c1dc98e |
hex | 13146293942 |
1311142132034 has 8 divisors (see below), whose sum is σ = 2247672226368. Its totient is φ = 561918056580.
The previous prime is 1311142132009. The next prime is 1311142132049. The reversal of 1311142132034 is 4302312411131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 1311142131994 and 1311142132012.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46826504702 + ... + 46826504729.
It is an arithmetic number, because the mean of its divisors is an integer number (280959028296).
Almost surely, 21311142132034 is an apocalyptic number.
1311142132034 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1311142132034 is a deficient number, since it is larger than the sum of its proper divisors (936530094334).
1311142132034 is an equidigital number, since it uses as much as digits as its factorization.
1311142132034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93653009440.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 1311142132034 its reverse (4302312411131), we get a palindrome (5613454543165).
The spelling of 1311142132034 in words is "one trillion, three hundred eleven billion, one hundred forty-two million, one hundred thirty-two thousand, thirty-four".
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