1311143010221 has 4 divisors (see below), whose sum is σ = 1430337829344. Its totient is φ = 1191948191100.

The previous prime is 1311143010209. The next prime is 1311143010241. The reversal of 1311143010221 is 1220103411131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311143010221 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1311143010193 and 1311143010202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311143010241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59597409545 + ... + 59597409566.

It is an arithmetic number, because the mean of its divisors is an integer number (357584457336).

Almost surely, 2^{1311143010221} is an apocalyptic number.

1311143010221 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1311143010221 is a deficient number, since it is larger than the sum of its proper divisors (119194819123).

1311143010221 is a wasteful number, since it uses less digits than its factorization.

1311143010221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119194819122.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1311143010221 its reverse (1220103411131), we get a palindrome (2531246421352).

The spelling of 1311143010221 in words is "one trillion, three hundred eleven billion, one hundred forty-three million, ten thousand, two hundred twenty-one".