Base | Representation |
---|---|
bin | 1011111011001011111010… |
… | …1111101010001100110101 |
3 | 1201102102220211011222012220 |
4 | 2332302332233222030311 |
5 | 3204304212212231203 |
6 | 43515151302032553 |
7 | 2522161500100101 |
oct | 276627657521465 |
9 | 51372824158186 |
10 | 13111440352053 |
11 | 41a559229a6aa |
12 | 1579102a18759 |
13 | 7415326c1934 |
14 | 334850622901 |
15 | 17b0d2e45653 |
hex | becbebea335 |
13111440352053 has 8 divisors (see below), whose sum is σ = 17482385156928. Its totient is φ = 8740727890944.
The previous prime is 13111440352039. The next prime is 13111440352063. The reversal of 13111440352053 is 35025304411131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13111440352053 - 210 = 13111440351029 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13111440352063) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57954225 + ... + 58180022.
It is an arithmetic number, because the mean of its divisors is an integer number (2185298144616).
Almost surely, 213111440352053 is an apocalyptic number.
It is an amenable number.
13111440352053 is a deficient number, since it is larger than the sum of its proper divisors (4370944804875).
13111440352053 is a wasteful number, since it uses less digits than its factorization.
13111440352053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 116171883.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 13111440352053 its reverse (35025304411131), we get a palindrome (48136744763184).
The spelling of 13111440352053 in words is "thirteen trillion, one hundred eleven billion, four hundred forty million, three hundred fifty-two thousand, fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •