13111440444101 has 4 divisors (see below), whose sum is σ = 13124999328672. Its totient is φ = 13097881559532.

The previous prime is 13111440444077. The next prime is 13111440444173. The reversal of 13111440444101 is 10144404411131.

13111440444101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13111440444101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111440444181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6779440835 + ... + 6779442768.

It is an arithmetic number, because the mean of its divisors is an integer number (3281249832168).

Almost surely, 2^{13111440444101} is an apocalyptic number.

It is an amenable number.

13111440444101 is a deficient number, since it is larger than the sum of its proper divisors (13558884571).

13111440444101 is an equidigital number, since it uses as much as digits as its factorization.

13111440444101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13558884570.

The product of its (nonzero) digits is 3072, while the sum is 29.

Adding to 13111440444101 its reverse (10144404411131), we get a palindrome (23255844855232).

The spelling of 13111440444101 in words is "thirteen trillion, one hundred eleven billion, four hundred forty million, four hundred forty-four thousand, one hundred one".