13111481117 has 4 divisors (see below), whose sum is σ = 14984549856. Its totient is φ = 11238412380.

The previous prime is 13111481113. The next prime is 13111481129. The reversal of 13111481117 is 71118411131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13111481117 - 2² = 13111481113 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13111481117.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111481113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936534359 + ... + 936534372.

It is an arithmetic number, because the mean of its divisors is an integer number (3746137464).

Almost surely, 2^13111481117 is an apocalyptic number.

It is an amenable number.

13111481117 is a deficient number, since it is larger than the sum of its proper divisors (1873068739).

13111481117 is an equidigital number, since it uses as much as digits as its factorization.

13111481117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1873068738.

The product of its digits is 672, while the sum is 29.

Adding to 13111481117 its reverse (71118411131), we get a palindrome (84229892248).

The spelling of 13111481117 in words is "thirteen billion, one hundred eleven million, four hundred eighty-one thousand, one hundred seventeen".