13111501505441 has 4 divisors (see below), whose sum is σ = 13118509257984. Its totient is φ = 13104493752900.

The previous prime is 13111501505437. The next prime is 13111501505449. The reversal of 13111501505441 is 14450510511131.

13111501505441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13111501505441 - 2² = 13111501505437 is a prime.

It is a super-2 number, since 2×13111501505441² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13111501505398 and 13111501505407.

It is not an unprimeable number, because it can be changed into a prime (13111501505449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3503873465 + ... + 3503877206.

It is an arithmetic number, because the mean of its divisors is an integer number (3279627314496).

Almost surely, 2^{13111501505441} is an apocalyptic number.

It is an amenable number.

13111501505441 is a deficient number, since it is larger than the sum of its proper divisors (7007752543).

13111501505441 is an equidigital number, since it uses as much as digits as its factorization.

13111501505441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7007752542.

The product of its (nonzero) digits is 6000, while the sum is 32.

The spelling of 13111501505441 in words is "thirteen trillion, one hundred eleven billion, five hundred one million, five hundred five thousand, four hundred forty-one".