Base | Representation |
---|---|
bin | 11101110011111110100010… |
… | …111111111011010110001111 |
3 | 122012020111020211000201112102 |
4 | 131303332202333323112033 |
5 | 114141142413013442033 |
6 | 1142505254132225315 |
7 | 36421521626356346 |
oct | 3563764277732617 |
9 | 565214224021472 |
10 | 131115201312143 |
11 | 3886070aa7a004 |
12 | 1285700776b23b |
13 | 5821158802ac9 |
14 | 245401c4d0b5d |
15 | 1025919876de8 |
hex | 773fa2ffb58f |
131115201312143 has 4 divisors (see below), whose sum is σ = 131118079657728. Its totient is φ = 131112322966560.
The previous prime is 131115201312133. The next prime is 131115201312187. The reversal of 131115201312143 is 341213102511131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131115201312143 - 228 = 131114932876687 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131115201312133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1439104463 + ... + 1439195568.
It is an arithmetic number, because the mean of its divisors is an integer number (32779519914432).
Almost surely, 2131115201312143 is an apocalyptic number.
131115201312143 is a deficient number, since it is larger than the sum of its proper divisors (2878345585).
131115201312143 is an equidigital number, since it uses as much as digits as its factorization.
131115201312143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2878345584.
The product of its (nonzero) digits is 2160, while the sum is 29.
Adding to 131115201312143 its reverse (341213102511131), we get a palindrome (472328303823274).
The spelling of 131115201312143 in words is "one hundred thirty-one trillion, one hundred fifteen billion, two hundred one million, three hundred twelve thousand, one hundred forty-three".
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