Base | Representation |
---|---|
bin | 10011000101000111111… |
… | …010011010011001110101 |
3 | 11122100100210112110211111 |
4 | 103011013322122121311 |
5 | 132440234402120432 |
6 | 2442202140035021 |
7 | 163505024014024 |
oct | 23050772323165 |
9 | 4570323473744 |
10 | 1311171520117 |
11 | 466079160648 |
12 | 192144832a71 |
13 | 96848716c84 |
14 | 476651468bb |
15 | 2418ea95347 |
hex | 13147e9a675 |
1311171520117 has 4 divisors (see below), whose sum is σ = 1311208601580. Its totient is φ = 1311134438656.
The previous prime is 1311171520103. The next prime is 1311171520121. The reversal of 1311171520117 is 7110251711131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1237169022961 + 74002497156 = 1112281^2 + 272034^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311171520117 - 215 = 1311171487349 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311171520147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18487642 + ... + 18558427.
It is an arithmetic number, because the mean of its divisors is an integer number (327802150395).
Almost surely, 21311171520117 is an apocalyptic number.
It is an amenable number.
1311171520117 is a deficient number, since it is larger than the sum of its proper divisors (37081463).
1311171520117 is an equidigital number, since it uses as much as digits as its factorization.
1311171520117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37081462.
The product of its (nonzero) digits is 1470, while the sum is 31.
The spelling of 1311171520117 in words is "one trillion, three hundred eleven billion, one hundred seventy-one million, five hundred twenty thousand, one hundred seventeen".
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