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131120022320303 = 301999434173697
BaseRepresentation
bin11101110100000011000010…
…010110100111010010101111
3122012020221200210121022110012
4131310003002112213102233
5114141232301203222203
61142511412351203435
736422052246304622
oct3564030226472257
9565227623538405
10131120022320303
1138862764342875
1212857b3221657b
135821746551663
1424543588bbdb9
151025aecc23bd8
hex7740c25a74af

131120022320303 has 4 divisors (see below), whose sum is σ = 131120456796000. Its totient is φ = 131119587844608.

The previous prime is 131120022320279. The next prime is 131120022320311. The reversal of 131120022320303 is 303023220021131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131120022320303 - 212 = 131120022316207 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131120022320383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216784850 + ... + 217388847.

It is an arithmetic number, because the mean of its divisors is an integer number (32780114199000).

Almost surely, 2131120022320303 is an apocalyptic number.

131120022320303 is a deficient number, since it is larger than the sum of its proper divisors (434475697).

131120022320303 is an equidigital number, since it uses as much as digits as its factorization.

131120022320303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 434475696.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 131120022320303 its reverse (303023220021131), we get a palindrome (434143242341434).

The spelling of 131120022320303 in words is "one hundred thirty-one trillion, one hundred twenty billion, twenty-two million, three hundred twenty thousand, three hundred three".

Divisors: 1 301999 434173697 131120022320303