1311200345041 has 4 divisors (see below), whose sum is σ = 1311948321892. Its totient is φ = 1310452368192.

The previous prime is 1311200345033. The next prime is 1311200345053. The reversal of 1311200345041 is 1405430021131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 22521305041 + 1288679040000 = 150071^2 + 1135200^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311200345041 - 2³ = 1311200345033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311200344997 and 1311200345015.

It is not an unprimeable number, because it can be changed into a prime (1311200342041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 373985796 + ... + 373989301.

It is an arithmetic number, because the mean of its divisors is an integer number (327987080473).

Almost surely, 2^{1311200345041} is an apocalyptic number.

It is an amenable number.

1311200345041 is a deficient number, since it is larger than the sum of its proper divisors (747976851).

1311200345041 is an equidigital number, since it uses as much as digits as its factorization.

1311200345041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 747976850.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1311200345041 its reverse (1405430021131), we get a palindrome (2716630366172).

The spelling of 1311200345041 in words is "one trillion, three hundred eleven billion, two hundred million, three hundred forty-five thousand, forty-one".