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131120153253442 = 265560076626721
BaseRepresentation
bin11101110100000011001010…
…001010000101011001000010
3122012020222000220222101221201
4131310003022022011121002
5114141233033213102232
61142511433345411414
736422055426233113
oct3564031212053102
9565228026871851
10131120153253442
1138862821241881
1212857b6a039b6a
135821767705aa2
14245436c04220a
151025b09488be7
hex7740ca285642

131120153253442 has 4 divisors (see below), whose sum is σ = 196680229880166. Its totient is φ = 65560076626720.

The previous prime is 131120153253437. The next prime is 131120153253449. The reversal of 131120153253442 is 244352351021131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 117262931097601 + 13857222155841 = 10828801^2 + 3722529^2 .

It is a super-2 number, since 2×1311201532534422 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (131120153253449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32780038313359 + ... + 32780038313362.

Almost surely, 2131120153253442 is an apocalyptic number.

131120153253442 is a deficient number, since it is larger than the sum of its proper divisors (65560076626724).

131120153253442 is an equidigital number, since it uses as much as digits as its factorization.

131120153253442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65560076626723.

The product of its (nonzero) digits is 86400, while the sum is 37.

The spelling of 131120153253442 in words is "one hundred thirty-one trillion, one hundred twenty billion, one hundred fifty-three million, two hundred fifty-three thousand, four hundred forty-two".

Divisors: 1 2 65560076626721 131120153253442