Base | Representation |
---|---|
bin | 11101110100000011001110… |
… | …111010111000011111001000 |
3 | 122012020222020111022210121022 |
4 | 131310003032322320133020 |
5 | 114141233214141421004 |
6 | 1142511445322132012 |
7 | 36422060416334606 |
oct | 3564031672703710 |
9 | 565228214283538 |
10 | 131120233154504 |
11 | 38862862355710 |
12 | 12857b90951008 |
13 | 582177b130119 |
14 | 24543788c0876 |
15 | 1025b114bd2be |
hex | 7740ceeb87c8 |
131120233154504 has 16 divisors (see below), whose sum is σ = 268200476907120. Its totient is φ = 59600105979280.
The previous prime is 131120233154501. The next prime is 131120233154527. The reversal of 131120233154504 is 405451332021131.
It is not an unprimeable number, because it can be changed into a prime (131120233154501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 745001324654 + ... + 745001324829.
It is an arithmetic number, because the mean of its divisors is an integer number (16762529806695).
Almost surely, 2131120233154504 is an apocalyptic number.
It is an amenable number.
131120233154504 is an abundant number, since it is smaller than the sum of its proper divisors (137080243752616).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131120233154504 is a wasteful number, since it uses less digits than its factorization.
131120233154504 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1490002649500 (or 1490002649496 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 131120233154504 its reverse (405451332021131), we get a palindrome (536571565175635).
The spelling of 131120233154504 in words is "one hundred thirty-one trillion, one hundred twenty billion, two hundred thirty-three million, one hundred fifty-four thousand, five hundred four".
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