Base | Representation |
---|---|
bin | 11101110100000011010011… |
… | …101001101001011001000001 |
3 | 122012020222110000200002202111 |
4 | 131310003103221221121001 |
5 | 114141233400001203210 |
6 | 1142511501235215321 |
7 | 36422062402055611 |
oct | 3564032351513101 |
9 | 565228400602674 |
10 | 131120312522305 |
11 | 388628a3134937 |
12 | 12857bb3447541 |
13 | 58217916cb812 |
14 | 2454385260a41 |
15 | 1025b1844988a |
hex | 7740d3a69641 |
131120312522305 has 16 divisors (see below), whose sum is σ = 160277937206400. Its totient is φ = 102958566859008.
The previous prime is 131120312522239. The next prime is 131120312522359. The reversal of 131120312522305 is 503225213021131.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 131120312522305 - 211 = 131120312520257 is a prime.
It is a super-2 number, since 2×1311203125223052 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1126501755 + ... + 1126618144.
It is an arithmetic number, because the mean of its divisors is an integer number (10017371075400).
Almost surely, 2131120312522305 is an apocalyptic number.
It is an amenable number.
131120312522305 is a deficient number, since it is larger than the sum of its proper divisors (29157624684095).
131120312522305 is a wasteful number, since it uses less digits than its factorization.
131120312522305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2253120120.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 131120312522305 its reverse (503225213021131), we get a palindrome (634345525543436).
The spelling of 131120312522305 in words is "one hundred thirty-one trillion, one hundred twenty billion, three hundred twelve million, five hundred twenty-two thousand, three hundred five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •