131120344215441 has 12 divisors (see below), whose sum is σ = 216452631720832. Its totient is φ = 74925910980216.

The previous prime is 131120344215359. The next prime is 131120344215493. The reversal of 131120344215441 is 144512443021131.

131120344215441 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 20 + 3 + 442 + 154 + 41 = 666.

It is not a de Polignac number, because 131120344215441 - 2³¹ = 131118196731793 is a prime.

It is a super-3 number, since 3×131120344215441³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131120344215396 and 131120344215405.

It is not an unprimeable number, because it can be changed into a prime (131120344225441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1040637652441 + ... + 1040637652566.

Almost surely, 2^{131120344215441} is an apocalyptic number.

It is an amenable number.

131120344215441 is a deficient number, since it is larger than the sum of its proper divisors (85332287505391).

131120344215441 is a wasteful number, since it uses less digits than its factorization.

131120344215441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2081275305020 (or 2081275305017 counting only the distinct ones).

The product of its (nonzero) digits is 46080, while the sum is 36.

Adding to 131120344215441 its reverse (144512443021131), we get a palindrome (275632787236572).

The spelling of 131120344215441 in words is "one hundred thirty-one trillion, one hundred twenty billion, three hundred forty-four million, two hundred fifteen thousand, four hundred forty-one".