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131120344215493 is a prime number
BaseRepresentation
bin11101110100000011010101…
…100010100010111111000101
3122012020222112020022021122021
4131310003111202202333011
5114141233431104343433
61142511504330403141
736422063235335563
oct3564032542427705
9565228466267567
10131120344215493
113886290a011456
1212858001b904b1
135821798147399
142454389550a33
151025b1b10a22d
hex7740d58a2fc5

131120344215493 has 2 divisors, whose sum is σ = 131120344215494. Its totient is φ = 131120344215492.

The previous prime is 131120344215359. The next prime is 131120344215521. The reversal of 131120344215493 is 394512443021131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95801772714244 + 35318571501249 = 9787838^2 + 5942943^2 .

It is a cyclic number.

It is not a de Polignac number, because 131120344215493 - 233 = 131111754280901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131120344215193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560172107746 + 65560172107747.

It is an arithmetic number, because the mean of its divisors is an integer number (65560172107747).

Almost surely, 2131120344215493 is an apocalyptic number.

It is an amenable number.

131120344215493 is a deficient number, since it is larger than the sum of its proper divisors (1).

131120344215493 is an equidigital number, since it uses as much as digits as its factorization.

131120344215493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 43.

The spelling of 131120344215493 in words is "one hundred thirty-one trillion, one hundred twenty billion, three hundred forty-four million, two hundred fifteen thousand, four hundred ninety-three".