131121212233303 has 4 divisors (see below), whose sum is σ = 131122873567440. Its totient is φ = 131119550899168.

The previous prime is 131121212233301. The next prime is 131121212233309. The reversal of 131121212233303 is 303332212121131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131121212233303 - 2¹ = 131121212233301 is a prime.

It is a super-3 number, since 3×131121212233303³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131121212233301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 830548675 + ... + 830706532.

It is an arithmetic number, because the mean of its divisors is an integer number (32780718391860).

Almost surely, 2^{131121212233303} is an apocalyptic number.

131121212233303 is a deficient number, since it is larger than the sum of its proper divisors (1661334137).

131121212233303 is an equidigital number, since it uses as much as digits as its factorization.

131121212233303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1661334136.

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 131121212233303 its reverse (303332212121131), we get a palindrome (434453424354434).

The spelling of 131121212233303 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, two hundred twelve million, two hundred thirty-three thousand, three hundred three".