Base | Representation |
---|---|
bin | 11101110100000100001001… |
… | …010101100010010100100011 |
3 | 122012021001202210111021220020 |
4 | 131310010021111202110203 |
5 | 114141242221041021011 |
6 | 1142512130452244523 |
7 | 36422123616632031 |
oct | 3564041125422443 |
9 | 565231683437806 |
10 | 131121213220131 |
11 | 388632155a3502 |
12 | 12858205010743 |
13 | 58218a61aaa04 |
14 | 245442cb1d551 |
15 | 1025b6c563006 |
hex | 774109562523 |
131121213220131 has 16 divisors (see below), whose sum is σ = 178693970400000. Its totient is φ = 85496340674528.
The previous prime is 131121213220121. The next prime is 131121213220147. The reversal of 131121213220131 is 131022312121131.
It is a cyclic number.
It is not a de Polignac number, because 131121213220131 - 217 = 131121213089059 is a prime.
It is a super-2 number, since 2×1311212132201312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131121213220121) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1880162631 + ... + 1880232368.
It is an arithmetic number, because the mean of its divisors is an integer number (11168373150000).
Almost surely, 2131121213220131 is an apocalyptic number.
131121213220131 is a deficient number, since it is larger than the sum of its proper divisors (47572757179869).
131121213220131 is a wasteful number, since it uses less digits than its factorization.
131121213220131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3760395258.
The product of its (nonzero) digits is 432, while the sum is 24.
Adding to 131121213220131 its reverse (131022312121131), we get a palindrome (262143525341262).
The spelling of 131121213220131 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, two hundred thirteen million, two hundred twenty thousand, one hundred thirty-one".
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