131121225141133 has 4 divisors (see below), whose sum is σ = 132594497333820. Its totient is φ = 129647952948448.

The previous prime is 131121225141121. The next prime is 131121225141157. The reversal of 131121225141133 is 331141522121131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 59969334656169 + 71151890484964 = 7743987^2 + 8435158^2 .

It is a cyclic number.

It is not a de Polignac number, because 131121225141133 - 2³³ = 131112635206541 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131121225141095 and 131121225141104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131121225171133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 736636096210 + ... + 736636096387.

It is an arithmetic number, because the mean of its divisors is an integer number (33148624333455).

Almost surely, 2^{131121225141133} is an apocalyptic number.

It is an amenable number.

131121225141133 is a deficient number, since it is larger than the sum of its proper divisors (1473272192687).

131121225141133 is an equidigital number, since it uses as much as digits as its factorization.

131121225141133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1473272192686.

The product of its digits is 4320, while the sum is 31.

Adding to 131121225141133 its reverse (331141522121131), we get a palindrome (462262747262264).

The spelling of 131121225141133 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, two hundred twenty-five million, one hundred forty-one thousand, one hundred thirty-three".