13112124431 has 4 divisors (see below), whose sum is σ = 14985285072. Its totient is φ = 11238963792.

The previous prime is 13112124401. The next prime is 13112124451. The reversal of 13112124431 is 13442121131.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2^k-13112124431 is a prime.

It is a super-2 number, since 2×13112124431² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13112124397 and 13112124406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112124401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936580310 + ... + 936580323.

It is an arithmetic number, because the mean of its divisors is an integer number (3746321268).

Almost surely, 2^13112124431 is an apocalyptic number.

13112124431 is a deficient number, since it is larger than the sum of its proper divisors (1873160641).

13112124431 is an equidigital number, since it uses as much as digits as its factorization.

13112124431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1873160640.

The product of its digits is 576, while the sum is 23.

Adding to 13112124431 its reverse (13442121131), we get a palindrome (26554245562).

The spelling of 13112124431 in words is "thirteen billion, one hundred twelve million, one hundred twenty-four thousand, four hundred thirty-one".