Base | Representation |
---|---|
bin | 1011111011001110011111… |
… | …0110100010101001111001 |
3 | 1201102111200212220211112121 |
4 | 2332303213312202221321 |
5 | 3204312120241201014 |
6 | 43515343540041241 |
7 | 2522214543145504 |
oct | 276634766425171 |
9 | 51374625824477 |
10 | 13112130022009 |
11 | 41a5906623977 |
12 | 1579275993221 |
13 | 741612555175 |
14 | 3348b806c13b |
15 | 17b123777124 |
hex | bece7da2a79 |
13112130022009 has 4 divisors (see below), whose sum is σ = 13198965320320. Its totient is φ = 13025294723700.
The previous prime is 13112130022001. The next prime is 13112130022027. The reversal of 13112130022009 is 90022003121131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13112130022009 - 23 = 13112130022001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13112130022001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43417648929 + ... + 43417649230.
It is an arithmetic number, because the mean of its divisors is an integer number (3299741330080).
Almost surely, 213112130022009 is an apocalyptic number.
It is an amenable number.
13112130022009 is a deficient number, since it is larger than the sum of its proper divisors (86835298311).
13112130022009 is an equidigital number, since it uses as much as digits as its factorization.
13112130022009 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 86835298310.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 13112130022009 in words is "thirteen trillion, one hundred twelve billion, one hundred thirty million, twenty-two thousand, nine".
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