1311213002201 has 4 divisors (see below), whose sum is σ = 1339111151232. Its totient is φ = 1283314853172.

The previous prime is 1311213002167. The next prime is 1311213002207. The reversal of 1311213002201 is 1022003121131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311213002201 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1311213002201.

It is not an unprimeable number, because it can be changed into a prime (1311213002207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13949074445 + ... + 13949074538.

It is an arithmetic number, because the mean of its divisors is an integer number (334777787808).

Almost surely, 2^{1311213002201} is an apocalyptic number.

It is an amenable number.

1311213002201 is a deficient number, since it is larger than the sum of its proper divisors (27898149031).

1311213002201 is an equidigital number, since it uses as much as digits as its factorization.

1311213002201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27898149030.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1311213002201 its reverse (1022003121131), we get a palindrome (2333216123332).

The spelling of 1311213002201 in words is "one trillion, three hundred eleven billion, two hundred thirteen million, two thousand, two hundred one".