131121311114141 has 4 divisors (see below), whose sum is σ = 131131743246300. Its totient is φ = 131110878981984.

The previous prime is 131121311114113. The next prime is 131121311114197. The reversal of 131121311114141 is 141411113121131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 129500644627225 + 1620666486916 = 11379835^2 + 1273054^2 .

It is a cyclic number.

It is not a de Polignac number, because 131121311114141 - 2¹⁴ = 131121311097757 is a prime.

It is a super-2 number, since 2×131121311114141² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131121311114141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131121311114041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5216047226 + ... + 5216072363.

It is an arithmetic number, because the mean of its divisors is an integer number (32782935811575).

Almost surely, 2^{131121311114141} is an apocalyptic number.

It is an amenable number.

131121311114141 is a deficient number, since it is larger than the sum of its proper divisors (10432132159).

131121311114141 is a wasteful number, since it uses less digits than its factorization.

131121311114141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10432132158.

The product of its digits is 288, while the sum is 26.

Adding to 131121311114141 its reverse (141411113121131), we get a palindrome (272532424235272).

The spelling of 131121311114141 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three hundred eleven million, one hundred fourteen thousand, one hundred forty-one".