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1311213303103 = 11119201209373
BaseRepresentation
bin10011000101001010011…
…001110011010100111111
311122100110201011021022111
4103011022121303110333
5132440331101144403
62442210231354451
7163506042116224
oct23051231632477
94570421137274
101311213303103
1146609a7a9840
12192156822a27
1396854286232
144766a90194b
152419359a56d
hex1314a67353f

1311213303103 has 4 divisors (see below), whose sum is σ = 1430414512488. Its totient is φ = 1192012093720.

The previous prime is 1311213303089. The next prime is 1311213303107. The reversal of 1311213303103 is 3013033121131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311213303103 - 221 = 1311211205951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311213303107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59600604676 + ... + 59600604697.

It is an arithmetic number, because the mean of its divisors is an integer number (357603628122).

Almost surely, 21311213303103 is an apocalyptic number.

1311213303103 is a deficient number, since it is larger than the sum of its proper divisors (119201209385).

1311213303103 is a wasteful number, since it uses less digits than its factorization.

1311213303103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119201209384.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 1311213303103 its reverse (3013033121131), we get a palindrome (4324246424234).

The spelling of 1311213303103 in words is "one trillion, three hundred eleven billion, two hundred thirteen million, three hundred three thousand, one hundred three".

Divisors: 1 11 119201209373 1311213303103