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13112133101 = 71184677931
BaseRepresentation
bin11000011011000101…
…10100010111101101
31020211210210101011022
430031202310113231
5203323201224401
610005034303525
7642634202204
oct141542642755
936753711138
1013112133101
115619503741
12265b287ba5
13130c6a2c52
148c55d823b
1551b20171b
hex30d8b45ed

13112133101 has 4 divisors (see below), whose sum is σ = 13296811104. Its totient is φ = 12927455100.

The previous prime is 13112133079. The next prime is 13112133103. The reversal of 13112133101 is 10133121131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13112133101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13112133101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112133103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92338895 + ... + 92339036.

It is an arithmetic number, because the mean of its divisors is an integer number (3324202776).

Almost surely, 213112133101 is an apocalyptic number.

It is an amenable number.

13112133101 is a deficient number, since it is larger than the sum of its proper divisors (184678003).

13112133101 is an equidigital number, since it uses as much as digits as its factorization.

13112133101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 184678002.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13112133101 its reverse (10133121131), we get a palindrome (23245254232).

The spelling of 13112133101 in words is "thirteen billion, one hundred twelve million, one hundred thirty-three thousand, one hundred one".

Divisors: 1 71 184677931 13112133101