1311214224403 has 4 divisors (see below), whose sum is σ = 1311216752200. Its totient is φ = 1311211696608.

The previous prime is 1311214224289. The next prime is 1311214224407. The reversal of 1311214224403 is 3044224121131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311214224403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311214224407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 170550 + ... + 1628347.

It is an arithmetic number, because the mean of its divisors is an integer number (327804188050).

Almost surely, 2^{1311214224403} is an apocalyptic number.

1311214224403 is a deficient number, since it is larger than the sum of its proper divisors (2527797).

1311214224403 is an equidigital number, since it uses as much as digits as its factorization.

1311214224403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2527796.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1311214224403 its reverse (3044224121131), we get a palindrome (4355438345534).

The spelling of 1311214224403 in words is "one trillion, three hundred eleven billion, two hundred fourteen million, two hundred twenty-four thousand, four hundred three".