13112153431541 has 4 divisors (see below), whose sum is σ = 13112346891084. Its totient is φ = 13111959972000.

The previous prime is 13112153431529. The next prime is 13112153431567. The reversal of 13112153431541 is 14513435121131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7569679203025 + 5542474228516 = 2751305^2 + 2354246^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112153431541 - 2¹⁴ = 13112153415157 is a prime.

It is a super-2 number, since 2×13112153431541² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112153451541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96628070 + ... + 96763671.

It is an arithmetic number, because the mean of its divisors is an integer number (3278086722771).

Almost surely, 2^{13112153431541} is an apocalyptic number.

It is an amenable number.

13112153431541 is a deficient number, since it is larger than the sum of its proper divisors (193459543).

13112153431541 is an equidigital number, since it uses as much as digits as its factorization.

13112153431541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 193459542.

The product of its digits is 21600, while the sum is 35.

Adding to 13112153431541 its reverse (14513435121131), we get a palindrome (27625588552672).

The spelling of 13112153431541 in words is "thirteen trillion, one hundred twelve billion, one hundred fifty-three million, four hundred thirty-one thousand, five hundred forty-one".