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1311222210131 = 1777130718243
BaseRepresentation
bin10011000101001010111…
…011110001111001010011
311122100111022220210110102
4103011022323301321103
5132440340341211011
62442211150323015
7163506210614231
oct23051273617123
94570438823412
101311222210131
114660a4832819
121921597b946b
1396856084472
144766bb7d951
152419425973b
hex1314aef1e53

1311222210131 has 4 divisors (see below), whose sum is σ = 1388352928392. Its totient is φ = 1234091491872.

The previous prime is 1311222210113. The next prime is 1311222210139. The reversal of 1311222210131 is 1310122221131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311222210131 - 210 = 1311222209107 is a prime.

It is a super-2 number, since 2×13112222101312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311222210139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38565359105 + ... + 38565359138.

It is an arithmetic number, because the mean of its divisors is an integer number (347088232098).

Almost surely, 21311222210131 is an apocalyptic number.

1311222210131 is a deficient number, since it is larger than the sum of its proper divisors (77130718261).

1311222210131 is an equidigital number, since it uses as much as digits as its factorization.

1311222210131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77130718260.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1311222210131 its reverse (1310122221131), we get a palindrome (2621344431262).

The spelling of 1311222210131 in words is "one trillion, three hundred eleven billion, two hundred twenty-two million, two hundred ten thousand, one hundred thirty-one".

Divisors: 1 17 77130718243 1311222210131