Base | Representation |
---|---|
bin | 10011000100001001010… |
… | …111101001111001001011 |
3 | 11122020122200002120020002 |
4 | 103010021113221321023 |
5 | 132431112242034011 |
6 | 2441510053553215 |
7 | 163440023065223 |
oct | 23041127517113 |
9 | 4566580076202 |
10 | 1310122221131 |
11 | 46568a9257a9 |
12 | 191ab134580b |
13 | 9670c2087b9 |
14 | 475a5a45083 |
15 | 2412c8c6c3b |
hex | 131095e9e4b |
1310122221131 has 2 divisors, whose sum is σ = 1310122221132. Its totient is φ = 1310122221130.
The previous prime is 1310122221103. The next prime is 1310122221139. The reversal of 1310122221131 is 1311222210131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310122221131 is a prime.
It is a super-2 number, since 2×13101222211312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310122221139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655061110565 + 655061110566.
It is an arithmetic number, because the mean of its divisors is an integer number (655061110566).
Almost surely, 21310122221131 is an apocalyptic number.
1310122221131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310122221131 is an equidigital number, since it uses as much as digits as its factorization.
1310122221131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1310122221131 its reverse (1311222210131), we get a palindrome (2621344431262).
The spelling of 1310122221131 in words is "one trillion, three hundred ten billion, one hundred twenty-two million, two hundred twenty-one thousand, one hundred thirty-one".
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