131122320023 has 4 divisors (see below), whose sum is σ = 131124103488. Its totient is φ = 131120536560.

The previous prime is 131122319989. The next prime is 131122320073. The reversal of 131122320023 is 320023221131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 320023221131 = 11807 ⋅27104533.

It is a cyclic number.

It is not a de Polignac number, because 131122320023 - 2¹² = 131122315927 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131122319977 and 131122320004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131122320073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 776486 + ... + 930147.

It is an arithmetic number, because the mean of its divisors is an integer number (32781025872).

Almost surely, 2^131122320023 is an apocalyptic number.

131122320023 is a deficient number, since it is larger than the sum of its proper divisors (1783465).

131122320023 is an equidigital number, since it uses as much as digits as its factorization.

131122320023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1783464.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 131122320023 its reverse (320023221131), we get a palindrome (451145541154).

The spelling of 131122320023 in words is "one hundred thirty-one billion, one hundred twenty-two million, three hundred twenty thousand, twenty-three".