13112233333303 has 6 divisors (see below), whose sum is σ = 14198453846304. Its totient is φ = 12103599999816.

The previous prime is 13112233333301. The next prime is 13112233333337. The reversal of 13112233333303 is 30333333221131.

It is not a de Polignac number, because 13112233333303 - 2¹ = 13112233333301 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112233333301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 38793589575 + ... + 38793589912.

It is an arithmetic number, because the mean of its divisors is an integer number (2366408974384).

Almost surely, 2^{13112233333303} is an apocalyptic number.

13112233333303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13112233333303 is a deficient number, since it is larger than the sum of its proper divisors (1086220513001).

13112233333303 is an equidigital number, since it uses as much as digits as its factorization.

13112233333303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 77587179513 (or 77587179500 counting only the distinct ones).

The product of its (nonzero) digits is 26244, while the sum is 31.

Adding to 13112233333303 its reverse (30333333221131), we get a palindrome (43445566554434).

The spelling of 13112233333303 in words is "thirteen trillion, one hundred twelve billion, two hundred thirty-three million, three hundred thirty-three thousand, three hundred three".