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13112301144305 = 5111012360450251
BaseRepresentation
bin1011111011001111001000…
…0011010100100011110001
31201102112010210220202012102
42332303302003110203301
53204312443043104210
643515412531510145
72522222021520356
oct276636203244361
951375123822172
1013112301144305
1141a5994182660
121579303158355
1374163bb3b26c
143348d2a9462d
1517b1337c9ea5
hexbecf20d48f1

13112301144305 has 16 divisors (see below), whose sum is σ = 17335146650688. Its totient is φ = 9441801000000.

The previous prime is 13112301144233. The next prime is 13112301144337. The reversal of 13112301144305 is 50344110321131.

It is a de Polignac number, because none of the positive numbers 2k-13112301144305 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1180219571 + ... + 1180230680.

It is an arithmetic number, because the mean of its divisors is an integer number (1083446665668).

Almost surely, 213112301144305 is an apocalyptic number.

It is an amenable number.

13112301144305 is a deficient number, since it is larger than the sum of its proper divisors (4222845506383).

13112301144305 is a wasteful number, since it uses less digits than its factorization.

13112301144305 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2360450368.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 13112301144305 its reverse (50344110321131), we get a palindrome (63456411465436).

The spelling of 13112301144305 in words is "thirteen trillion, one hundred twelve billion, three hundred one million, one hundred forty-four thousand, three hundred five".

Divisors: 1 5 11 55 101 505 1111 5555 2360450251 11802251255 25964952761 129824763805 238405475351 1192027376755 2622460228861 13112301144305