13112301144233 has 2 divisors, whose sum is σ = 13112301144234. Its totient is φ = 13112301144232.

The previous prime is 13112301144203. The next prime is 13112301144337. The reversal of 13112301144233 is 33244110321131.

13112301144233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12552090809449 + 560210334784 = 3542893^2 + 748472^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112301144233 - 2¹⁰ = 13112301143209 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13112301144196 and 13112301144205.

It is not a weakly prime, because it can be changed into another prime (13112301144203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556150572116 + 6556150572117.

It is an arithmetic number, because the mean of its divisors is an integer number (6556150572117).

Almost surely, 2^{13112301144233} is an apocalyptic number.

It is an amenable number.

13112301144233 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112301144233 is an equidigital number, since it uses as much as digits as its factorization.

13112301144233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13112301144233 its reverse (33244110321131), we get a palindrome (46356411465364).

The spelling of 13112301144233 in words is "thirteen trillion, one hundred twelve billion, three hundred one million, one hundred forty-four thousand, two hundred thirty-three".