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131123042313 = 343707680771
BaseRepresentation
bin111101000011110001…
…0101101100000001001
3110112110012010201001120
41322013202231200021
54122014444323223
6140123113505453
712321231320124
oct1720742554011
9415405121046
10131123042313
11506775a247a
12214b4a12289
13c498762603
1464bc6c53bb
15362674bbe3
hex1e878ad809

131123042313 has 4 divisors (see below), whose sum is σ = 174830723088. Its totient is φ = 87415361540.

The previous prime is 131123042291. The next prime is 131123042317. The reversal of 131123042313 is 313240321131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131123042313 - 210 = 131123041289 is a prime.

It is not an unprimeable number, because it can be changed into a prime (131123042317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21853840383 + ... + 21853840388.

It is an arithmetic number, because the mean of its divisors is an integer number (43707680772).

Almost surely, 2131123042313 is an apocalyptic number.

It is an amenable number.

131123042313 is a deficient number, since it is larger than the sum of its proper divisors (43707680775).

131123042313 is an equidigital number, since it uses as much as digits as its factorization.

131123042313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43707680774.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 131123042313 its reverse (313240321131), we get a palindrome (444363363444).

The spelling of 131123042313 in words is "one hundred thirty-one billion, one hundred twenty-three million, forty-two thousand, three hundred thirteen".

Divisors: 1 3 43707680771 131123042313