1311231120043 has 16 divisors (see below), whose sum is σ = 1455617640960. Its totient is φ = 1173543470496.

The previous prime is 1311231120029. The next prime is 1311231120091. The reversal of 1311231120043 is 3400211321131.

It is a cyclic number.

It is not a de Polignac number, because 1311231120043 - 2⁹ = 1311231119531 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311231119996 and 1311231120023.

It is not an unprimeable number, because it can be changed into a prime (1311231126043) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9962853 + ... + 10093606.

It is an arithmetic number, because the mean of its divisors is an integer number (90976102560).

Almost surely, 2^{1311231120043} is an apocalyptic number.

1311231120043 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1311231120043 is a deficient number, since it is larger than the sum of its proper divisors (144386520917).

1311231120043 is a wasteful number, since it uses less digits than its factorization.

1311231120043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20056626.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1311231120043 its reverse (3400211321131), we get a palindrome (4711442441174).

The spelling of 1311231120043 in words is "one trillion, three hundred eleven billion, two hundred thirty-one million, one hundred twenty thousand, forty-three".