13112313000301 has 4 divisors (see below), whose sum is σ = 13133564723772. Its totient is φ = 13091061276832.

The previous prime is 13112313000299. The next prime is 13112313000337. The reversal of 13112313000301 is 10300031321131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1930846423401 + 11181466576900 = 1389549^2 + 3343870^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112313000301 - 2¹ = 13112313000299 is a prime.

It is a super-2 number, since 2×13112313000301² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112313000001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10625860810 + ... + 10625862043.

It is an arithmetic number, because the mean of its divisors is an integer number (3283391180943).

Almost surely, 2^{13112313000301} is an apocalyptic number.

It is an amenable number.

13112313000301 is a deficient number, since it is larger than the sum of its proper divisors (21251723471).

13112313000301 is an equidigital number, since it uses as much as digits as its factorization.

13112313000301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21251723470.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13112313000301 its reverse (10300031321131), we get a palindrome (23412344321432).

The spelling of 13112313000301 in words is "thirteen trillion, one hundred twelve billion, three hundred thirteen million, three hundred one", and thus it is an aban number.